This is in reference to the question previously asked
The problem here is, each slider
controls the other. It results in feedback.
How do I possibly stop it?
$(function() {
$("#slider").slider({ slide: moveSlider2 });
$("#slider1").slider({ slide: moveSlider1 });
function moveSlider2( e, ui )
{
$('#slider1').slider( 'moveTo', Math.round(ui.value) );
}
function moveSlider1( e, ui )
{
$('#slider').slider( 'moveTo', Math.round(ui.value) );
}
});
This is sort of a hack, but works:
$(function () {
var slider = $("#slider");
var slider1 = $("#slider1");
var sliderHandle = $("#slider").find('.ui-slider-handle');
var slider1Handle = $("#slider1").find('.ui-slider-handle');
slider.slider({ slide: moveSlider1 });
slider1.slider({ slide: moveSlider });
function moveSlider( e, ui ) {
sliderHandle.css('left', slider1Handle.css('left'));
}
function moveSlider1( e, ui ) {
slider1Handle.css('left', sliderHandle.css('left'));
}
});
Basically, you avoid the feedback by manipulating the css directly, not firing the slide event.