Numbering Array items numerically

Question

Alright, so I tried implementing the bubble sort algorithm into my code, but now my output for the second array (in my code) is giving me a ton of zeros. Can anybody tell me what is wrong with my code and how I can fix it so the zeros are removed and the only thing that remains in the output for my second array are the fixed numerically?

public static void main(String[] args) {

        System.out.println("Input up to '10' numbers for current array: ");

        int[] array1 = new int[10];
        int i;

        Scanner scan = new Scanner(System.in);

        for (i = 0; i < 10; i++) {
            System.out.println("Input a number for " + (i + 1) + ": ");
            int input = scan.nextInt();
            if (input == -9000) {
                break;
            } else {
                array1[i] = input;
            }
        }

        System.out.println("\n" + "Original Array: ");

        for (int j = 0; j < i; j++) {

            System.out.println((j + 1) + ": " + array1[j]);
        }

        int[] array2 = new int[i];

        System.out.println("\n" + "Organized Array: ");

        for (int j = 0; j < i; j++) {

            int temp;
            boolean organized = false;

            while (organized == false) {
                organized = true;


            for (i = 0; i < array1.length - 1; i++) {

                if (array1[i] > array1[i + 1]) {
                    temp = array1[i + 1];
                    array1[i + 1] = array1[i];
                    array1[i] = temp;
                    organized = false;
                }
            }

            }
            for (i = 0; i < array1.length; i++) {
                System.out.println(array1[i]);
            }
            scan.close();

        }
    }
}

Answer 1

Copy your array1 to an array2 of the correct length before sorting, something like

for (i = 0; i < 10; i++) {
    System.out.println("Input a number for " + (i + 1) + ": ");
    int input = scan.nextInt();
    if (input == -9000) {
        break;
    }
    array1[i] = input;
}
int[] array2 = Arrays.copyOfRange(array1, 0, i);
System.out.println("Before sorting: " + Arrays.toString(array2));
Arrays.sort(array2); // <-- How I would sort.
System.out.println("After sorting: " + Arrays.toString(array2));

The reason this is necessary is because i might not be 10 in which case your array contains 0(s) to fill the other positions.

Is it possible to move all my numbers from Array 1 to Array 2 using a for-loop?

Yes. You could implement a copyOfRange function with a for loop,

private static int[] copyOfRange(int[] arr, int start, int end) {
    int pos = 0;
    int[] out = new int[end - start];
    for (int i = start; i < end; i++) {
        out[pos] = arr[i];
        pos++;
    }
    return out;
}

the built-in version is almost certainly better.