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How to use Octave/Matlab Inline function in Scilab

How to use this Octave/Matlab inline function in Scilab?

u = inline('t>=0') where t=0:0.001:1.
y = (u(t-0.2)-u(t-0.3))

I tried it in Scilab as

deff('[u]=f(t)','u=(t>=0)')

But I am getting an error as "invalid index" in determining 'y'.

Solution

  • Unlike in Matlab, invoking (t>=0) gives you a boolean vector, its entries are True or False. Since you want 1s and 0s, you need bool2s to convert from boolean to integers: 

    deff('[u]=f(t)','u=bool2s(t>=0)')

    After that you can invoke the function like any other: 

    t = 0:0.001:1
y = u(t-0.2)-u(t-0.3)
plot(t,y)

    plot

    Personally, I never see the need for inline functions in Scilab. If I were writing the above, I would declare the function normally: 

    function y = u(t)
    y = bool2s(t>=0)
endfunction

    Unlike Matlab, Scilab allows you to have such functions appear wherever you want them in the script.