How to 'return' outside function definition in typescript

Question

1. I need to rewrite my tampermonkey script on typescript.

2. What is correct way to rewrite this javascript on typescript?

   if (window.top != window.self ) {
       return;
   }
   

Main goal is to stop executing script if it's running not in window.top.

Typescript compiler write ERROR TS1108: A 'return' statement can only be used within a function body.

Answer 1

You cannot return outside function, but using throw Exception you can stop execution userscipts (tampermonkey) too:

if (window.top != window.self) {
    throw new Error("Not on top");
}