ASC Visual Basic for Java

I need a function on Java that do the same as ASC function on Visual Basic. I've had looking for it on internet, but I can't found the solution.

The String that I have to know the codes was created on Visual Basic. It's according to ISO 8859-1 and Microsoft Windows Latin-1 characters. The ASC function on Visual Basic knows those codes, but in Java, I can't find a function that does the same thing.

I know in Java this sentence:

String myString = "ÅÛ–ßÕÅÝ•ÞÃ";
int first = (int)string.chartAt(0); // "Å"- VB and Java returns: 197
int second = (int)string.chartAt(0); // "Û" - VB and Java returns: 219
int third = (int)string.chartAt(0); // "–" - VB returns: 150 and Java returns: 8211

The first two characters, I haven't had problem, but the third character is not a ASCII code.

How can I get same codes in VB and Java?

Solution

First of all, note that ISO 8859-1 != Windows Latin-1. (See http://en.wikipedia.org/wiki/Windows-1252)

The problem is that Java encodes characters as UTF16, so casting to int will generally result in the Unicode value of the char.

To get the Latin-1 encoding of a char, first convert it to a Latin-1 encoded byte array:

public class Encoding {

    public static void main(String[] args) {
        // Cp1252 is Windows codepage 1252
        byte[] bytes = "ÅÛ–ßÕÅÝ•ÞÃ".getBytes(Charset.forName("Cp1252"));
        for (byte b: bytes) {
            System.out.println(b & 255);
        }
    }

}

prints: