public final class Test{
public static void main(String args[]) throws Exception {
BigDecimal bigDecimal_One = BigDecimal.ONE;
System.out.println(bigDecimal_One);
bigDecimal_One.add(BigDecimal.ONE);// 1. As I have not set bigDecimal_One = bigDecimal_One.add(BigDecimal.ONE) hence variable Value would be unchanged
System.out.println(bigDecimal_One);
addTenTo(bigDecimal_One);// 2. I wanted to know why still value is unchanged despite reference pointing to new value
System.out.println(bigDecimal_One);
}
public static void addTenTo(BigDecimal value) {
value = value.add(BigDecimal.TEN);
System.out.println("Inside addTenTo value = "+value);
}
}
When I run this program I get below Output
1
Inside addTenTo value = 11
1
Could someone please explain why the value of variable bigDecimal_One
still unchanged even when reference has been assigned to new Value in the method addTenTo
(i.e. 11
)?
My answer is inline...
public static void addTenTo(BigDecimal value) {
value = value.add(BigDecimal.TEN); // `value` here is a local variable, which does not affect the parameter-`value`
System.out.println("Inside addTenTo value = "+value);
}