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c++visual-c++c-preprocessorpreprocessor-directive

Using preprocessor directives to define the output path

Using the following pseudo-code:

#define BUILD_PATH "C:/MyBuild/"
#define BUILD_NAME "mydll.dll"
// Set build path here

representing how I would like to build the current project (a dll) into C:/MyBuild/mydll.dll, how would I accomplish this by only using preprocessor directives?

Solution

  • I may be misunderstanding, but I really cannot understand WHY you want to do this but it is doable:

    #pragma comment( linker, "/out:c:\mydll.dll" )

    I cannot re-iterate enough exactly how much you don't want to be doing this though ...

    If you want to GET the output path via pre-processor info then, I'm afraid ... you can't. That info comes from several steps after the pre-processor so there is no way the pre-processor could get that info.