I have a cell array of size m x 1 and each cell is again s x t cell array (size varies). I would like to concatenate vertically. The code is as follows:
function(cell_out) = vert_cat(cell_in)
[row,col] = cellfun(@size,cell_in,'Uni',0);
fcn_vert = @(x)([x,repmat({''},size(x,1),max(cell2mat(col))-size(x,2))]);
cell_out = cellfun(fcn_vert,cell_in,'Uni',0); % Taking up lot of time
cell_out = vertcat(cell_out{:});
end
Step 3 takes a lot of time. Is it the right way to do or is there any another faster way to achieve this?
I used this pice of code to generate data:
%generating some dummy data
m=1000;
s=100;
t=100;
cell_in=cell(m,1);
for idx=1:m
cell_in{idx}=cell(randi(s),randi(t));
end
Applying some minor modifications, I was able to speed up the code by a factor of 5
%Minor modifications of the original code
%use arrays instead of cells for row and col
[row,col] = cellfun(@size,cell_in);
%claculate max(col) once
tcol=max(col);
%use cell instead of repmat to generate an empty cell
fcn_vert = @(x)([x,cell(size(x,1),tcol-size(x,2))]);
cell_out = cellfun(fcn_vert,cell_in,'Uni',0); % Taking up lot of time
cell_out = vertcat(cell_out{:});
Using simply a for loop is even faster, because the data is only moved once
%new approac. Basic idea: move every data only once
[row,col] = cellfun(@size,cell_in);
trow=sum(row);
tcol=max(col);
r=1;
cell_out2 = cell(trow,tcol);
for idx=1:numel(cell_in)
cell_out2(r:r+row(idx)-1,1:col(idx))=cell_in{idx};
r=r+row(idx);
end