I have tried it by using different numbers in place of 50 and got different answers. Please can anyone tell me the calculation of this number.
There is no "calculation" behind this number. Quite simply, c()
creates a vector:
> c(1:10, 50)
[1] 1 2 3 4 5 6 7 8 9 10 50
and mean()
returns the mean of this vector (the sum divided by the length). If you vary the number, the mean also varies.
In statistics, a number like 50 here is known as an outlier. One way to obtain an average (or, formally, a measure of central tendency) that's robust to outliers is by computing the median:
> median(c(1:10, -100))
[1] 5
> median(c(1:10, 50))
[1] 6
> median(c(1:10, 5000))
[1] 6
Compare this with the means of the same vectors:
> mean(c(1:10, -100))
[1] -4.090909
> mean(c(1:10, 50))
[1] 9.545455
> mean(c(1:10, 5000))
[1] 459.5455
This example shows how a single outlying observation can greatly affect the mean but not the median.