I am trying to use boost lambda to avoid having to write trivial functors. For example, I want to use the lambda to access a member of a struct or call a method of a class, eg:
#include <vector>
#include <utility>
#include <algorithm>
#include <boost/lambda/lambda.hpp>
using namespace std;
using namespace boost::lambda;
vector< pair<int,int> > vp;
vp.push_back( make_pair<int,int>(1,1) );
vp.push_back( make_pair<int,int>(3,2) );
vp.push_back( make_pair<int,int>(2,3) );
sort(vp.begin(), vp.end(), _1.first > _2.first );
When I try and compile this I get the following errors:
error C2039: 'first' : is not a member of 'boost::lambda::lambda_functor<T>'
with
[
T=boost::lambda::placeholder<1>
]
error C2039: 'first' : is not a member of 'boost::lambda::lambda_functor<T>'
with
[
T=boost::lambda::placeholder<2>
]
Since vp contains pair<int,int>
I thought that _1.first should work. What I am doing wrong?
What you want is something akin to:
#include <boost/lambda/bind.hpp> // new header
// typedefs make code easier
typedef pair<int,int> pair_type;
typedef vector<pair_type> vector_type;
vector_type vp;
vp.push_back( make_pair(1,1) ); // don't specify template arguments!
vp.push_back( make_pair(3,2) ); // the entire point of make_pair is
vp.push_back( make_pair(2,3) ); // to deduce them.
sort(vp.begin(), vp.end(),
bind(&pair_type::first, _1) > bind(&pair_type::first, _2) );