Well the title is a mouthful but I couldn't come up with a better one, ideas welcome.
Anyhow, I have a javascript object containing classes as properties. I want to create another object which is in every aspect equal to the first one by subclassing it. I'm gonna try to sum it up:
var L1 = {};
L1.Foo = function() {/*...*/};
L1.Bar = function() {/*...*/};
//...
L1.Baz = function() {/*...*/};
var L2 = {};
L2.Foo = function() { L1.Foo.call(this); /*possibily some other code here*/ };
L2.Foo.prototype = Object.create(L1.Foo.prototype);
L2.Foo.prototype.constructor = L2.Foo;
L2.Bar = function() { L1.Bar.call(this); /*possibily some other code here*/ };
L2.Bar.prototype = Object.create(L1.Bar.prototype);
L2.Bar.prototype.constructor = L2.Bar;
//...
L2.Baz = function() { L1.Baz.call(this); /*possibily some other code here*/ };
L2.Baz.prototype = Object.create(L1.Baz.prototype);
L2.Baz.prototype.constructor = L2.Baz;
var foo = new L2.Foo();
console.log(foo); //L2.Foo
var bar = new L2.Bar();
console.log(bar); //L2.Bar
var baz = new L2.Baz();
console.log(baz); //L2.Baz
First, working version.
I told myself: "huh, looks like there a pattern here" so I went and modified my code as follows:
//first 10 lines unaltered
for(prop in L1) {
L2[prop] = function() { L1[prop].call(this); /*Call super method by default,
unless overriden below*/ };
L2[prop].prototype = Object.create(L1[prop].prototype);
L2[prop].prototype.constructor = L2[prop];
}
//Here I decide that I want to override only the constructor
//for Foo, so naturally:
L2.Foo.prototype.constructor = function() {
L1.Foo.call(this);
this.someOtherProperty = "foo";
};
var foo = new L2.Foo();
console.log(foo); //L2.(anonymous function)?
console.log(foo.someOtherProperty); //undefined?
var bar = new L2.Bar();
console.log(bar); //L2.(anonymous function)?
var baz = new L2.Baz();
console.log(baz); //L2.(anonymous function)?
Second, not-so-working version.
What I am getting wrong?
"huh, looks like there a pattern here" so I went and modified my code as follows:
for(prop in L1) { L2[prop] = function() { L1[prop].call(this);
You've hit the common closure in a loop problem - all your L2
functions are actually calling L1.Baz
on their new instance as prop
will have the value "Baz"
. See the linked question for how to fix this.
Also, notice that none of your constructors does pass its arguments to the super call, which might bite you as well.
Here I decide that I want to override only the constructor for Foo, so naturally:
L2.Foo.prototype.constructor = function() { L1.Foo.call(this); this.someOtherProperty = "foo"; };
What I am getting wrong?
Overwriting the .constructor
property on a prototype object does nothing. Your code is still invoking new L2.Foo
, not new L2.Foo.prototype.constructor
. You might want to have a look at how the new
keyword works.
Instead, you really need to replace L2.Foo
. This can be done with this pattern:
L2.Foo = (function (original) {
function Foo() {
original.apply(this, arguments); // apply old L2.Foo constructor
this.someOtherProperty = "foo"; // set property
}
Foo.prototype = original.prototype; // reset prototype
Foo.prototype.constructor = Foo; // fix constructor property
return Foo;
})(L2.Foo);
(or you just put your standard pattern from the first version). If this does get too repetitive, you might also do the .prototype
and .constructor
setup programmatically:
// whole code
var L2 = {
Foo: function() {
L1.Foo.call(this);
this.someOtherProperty = "foo";
}
// … other overwritten constructors
};
for (var prop in L1) {
if (!L2[prop]) // unless overridden above, create default that only…
(function(parent) {
L2[prop] = function() {
parent.apply(this, arguments); // calls super
};
}(L1[prop]));
L2[prop].prototype = Object.create(L1[prop].prototype);
L2[prop].prototype.constructor = L2[prop];
}