I've been going through some tutorials around luabridge for accessing c++ from lua but I've hit a problem I can't seem to find an answer to by searching google.
I've setup a sample program to run the script and access lua from c++, which works fine. But when I try to register a function in the global namespace it complains during runtime - compiling just fine.
#include <iostream>
#include <string>
#include "../LuaBridge/LuaBridge.h"
using namespace luabridge;
void printMessage(const std::string& s) {
std::cout << s << std::endl;
}
int main() {
lua_State* L = luaL_newstate();
getGlobalNamespace(L).addFunction("printMessage", printMessage);
luaL_dofile(L, "script.lua");
luaL_openlibs(L);
lua_pcall(L, 0, 0, 0);
LuaRef s = getGlobal(L, "testString");
LuaRef n = getGlobal(L, "number");
std::string luaString = s.cast<std::string>();
int answer = n.cast<int>();
std::cout << luaString << std::endl;
std::cout << "And here's our number:" << answer << std::endl;
}
So, this code with the addFunction call gives me this error
Lua: /home/linuxxon/Programming/kingdoms-online/Script/Lua/../LuaBridge/detail/Namespace.h:1080: luabridge::Namespace& luabridge::Namespace::addFunction(const char*, FP) [with FP = void (*)(const std::basic_string<char>&)]: Assertion `(lua_type(L, (-1)) == 5)' failed.
Withouth the addFunction call I get what is expected of the script.
Is there perhaps something obvious that I have missed, since I haven't found anything like it?
I would greatly appreciate all help!
The problem was that the
luaL_openlibs(L);
was after the script had been run. The problem was in the tutorial I was following, I encountered the same thing before in the beginning of my tries with lua.
It all works perfectly by calling it after creating the new lua state.