I show links to 240 images on a page. The real images are uploaded by users. I tried to avoid showing an empty image if users did not upload it yet. jQuery did not work for me because of conflicts, so I have to do it in pure JavaScript.
image(s) links:
<img class="photo240" src="http://www.example.com/i/%%GLOBAL__AuthorID%%/p/b01.jpg" onerror="imgError()">
My JavaScript:
function imgError()
{
alert('The image could not be loaded.');
var _aryElm=document.getElementsByTagName('img'); //return an array with every <img> of the page
for( x in _aryElm) {
_elm=_aryElm[x];
_elm.className="photo240off";
}
}
The style photo240off
equals to display:none
.
Right now, whenever an image misses, all the images are turned to style photo240off and I want only the missing image to be hidden. So there is something wrong with my script.
(the overall script works well, because I get the alert).
Use this
to get the image with the error.
Change to:
onerror="imgError(this)"
Then the function can be:
function imgError(el) {
alert('The image could not be loaded.');
el.className = "photo240off";
}