I need to set this layout visible when i click a button, my java is like:
Layout propLayout = (Layout) findViewById(R.id.properLayout);
public void propsBtn(View view) {
propLayout.setVisiblity(View.Visible);
}
I know I'm totally wrong with the layout line! I'll be very grateful if someone could show me how to set it right :)
This is my XML:
<FrameLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="@color/mainBackGround"
tools:context="com.myapplication2.app.MainActivity">
<LinearLayout
android:layout_width="match_parent"
android:layout_height="match_parent">
<RelativeLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:padding="8dp">
...contents...
</RelativeLayout>
</LinearLayout>
<LinearLayout
android:layout_width="match_parent"
android:layout_height="match_parent"
android:visibility="gone"
android:id="@+id/properLayout">
<RelativeLayout
android:orientation="horizontal"
android:layout_width="match_parent"
android:layout_height="300dp"
android:layout_gravity="bottom"
android:padding="8dp">
...contents...
</RelativeLayout>
</LinearLayout>
DerGolem gave the right answer but he then deleted it, so I report it here now:
//First we set visibility value of interested layout either to gone, visible or invisible
android:visibility="gone"
Then under onCreate write like:
//specify the button that has to handle visibility
ImageButton properties = (ImageButton) findViewById(R.id.propBtn);
//And the layout we want to change is visibility
final LinearLayout propLayout = (LinearLayout) findViewById(R.id.properLayout);
properties.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
if (propLayout.getVisibility() == View.VISIBLE){
propLayout.setVisibility(View.INVISIBLE);
} else {
propLayout.setVisibility(View.VISIBLE);
}
}
});