Finding out the type of invoked method in JDT

Question

In this code, prosseek.B#bar() method invokes prosseek.SuperA#foo().

package prosseek;

public class SuperA {
    int i = 0;
    public void foo()
    {
        System.out.println(i);
    }
}

public class B {
    public void bar()
    {
        SuperA a = new SuperA();
        a.foo();
    }
}

I need to detect the type of foo() invoked in bar(). I use ASTVisitor to detect the MethodInvocation code (a.foo()), but I'm not sure what should I do in order to get the SuperA type from it.

ICompilationUnit icu = type.getCompilationUnit();
final ASTParser parser = ASTParser.newParser(AST.JLS3);
parser.setKind(ASTParser.K_COMPILATION_UNIT);
parser.setSource(icu);
parser.setResolveBindings(true); // we need bindings later on
CompilationUnit unit = (CompilationUnit) parser.createAST(null);

unit.accept(new ASTVisitor() {
    public boolean visit(MethodInvocation methodInvocation)
    {
        // ???

        return false;
    }
}

ADDED

I got the hint from JDT fundamentals tutorial.

I tried the following code:

IBinding binding = methodInvocation.resolveTypeBinding();
IType type = (IType)binding.getJavaElement();
if (type == null)
    return false;

However, I got null for the return value of binding.getJavaElement();

Answer 1

Instead of taking the type of the MethodInvocation, may be you need to take the type from the Expression. I have not tested this, but this might help.

public boolean visit(MethodInvocation node) {
    Expression exp = node.getExpression();
    ITypeBinding typeBinding = node.getExpression().resolveTypeBinding();
    System.out.println("Type: " + typeBinding.toString());
}