We are trying to avoid iframe and instead use javascript, jquery, jsonp and php based web widgets for our displaying content from our cross-domain html site. We want to display the full page as-is within the widget but from all the tutorials we read, its mentioned that we need to provide JSON datatype in order for cross-domain JSONP to work.
Here's what we tried -
Main JS
function render() {
jQuery.getJSON(serverFQDN + '/widget.php?callback=?', {
install_url: window.location.href
}, serverResponse);
}
function serverResponse(data) {
jQuery(container).html(data.html);
}
Widget.php
<?php echo $_GET['callback'] ?>({
"html": "<?php echo 'hello'; ?>"
});
We are able to display simple html entities like -
<?php echo $_GET['callback'] ?>({"html": "<li>TEST</li>"
});
But not the full page i.e.
<?php
$url = "http://localhost/page.html";
$curl = curl_init($url);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);
$output = curl_exec($curl);
curl_close($curl);
$output = json_encode($output);
echo $_GET['callback'] ?>({"html": "<?php echo $output; ?>"
});
You should use cURL or Firebug to check, but I think you are double-JSON-encoding your HTML.
It's also not clear why you write:
echo $_GET['callback'] ?>({"html": "<?php echo $output; ?>" });
instead of
echo $_GET['callback'] ?>({"html": $output });
EDIT: Never mind, I have it. You are JSON-encoding just to Javascript-encode -- but you have an extra set of quotation marks!
if $output is "<li>TEST</li>"
, then the file you are creating is
jsonpCallback({"html" : ""<li>TEST</li>""});
Uh, I think. Like I said, use cURL or Firebug to check the actual output.