I want to create multiple flyouts in a single HTML page using jQuery. Please have a look at the code below.
<div>123
<p style="display:none">
<a href="#">1</a>
<a href="#">2</a>
<a href="#">3</a>
</p>
</div>
<div>ABC
<p style="display:none">
<a href="#">a</a>
<a href="#">b</a>
<a href="#">c</a>
</p>
</div>
For now, there are only two divs that have different content. I want, when the div is clicked, p tag (nested inside it) to show/hide.
My knowlwdge of jquery is very limited and to achieve it my jquery code is like this.
<script>
$(document).ready(function(){
$("div").click(function(){
$(this p).toggle();
});
});
</script>
Which, of course is not working. Also there may be more than two divs on the same page and would have similar flyout.
What should I do to achieve this?
Any help would be greatly appreciated.
Thanking you in anticipation.
Regards Parvez A.
HTML Tweaked:
<div class="toggle_this">123
<p style="display:none">
<a href="#">1</a>
<a href="#">2</a>
<a href="#">3</a>
</p>
</div>
<div class="toggle_this">ABC
<p style="display:none">
<a href="#">a</a>
<a href="#">b</a>
<a href="#">c</a>
</p>
</div>
Javascript:
$(document).ready(function(){
$(".toggle_this").click(function(){
console.log('divs been hit');
$(this).children().toggle();
});
});
Please refer the working code in the link: http://jsfiddle.net/UaCLn/5/