In what scenario 'this' pointer is passed to the class methods?

Question

I was doing some reading on the 'this' pointer, and I think I understand it more than I originally did, but I still need some clarification. So, by my understanding, if you have

class Simple
{
private:
    int m_nID;

public:
    Simple(int nID)
    {
        SetID(nID);
    }

    void SetID(int nID) { m_nID = nID; }
    int GetID() { return m_nID; }
};

The SetID(int nID) function actually is semantically converted into:

void SetID(Simple* const this, int nID) { this->m_nID = nID; }

It makes sense that, there is a this pointer for all member functions of a class, for the most part. But what happens if you have a member function that takes no arguments? Is there a 'this' pointer? If so, does it point to the return type instead of the argument type?

Answer 1

But what happens if you have a member function that takes no arguments? Is there a 'this' pointer? If so, does it point to the return type instead of the argument type?

Even your method do not have any argument, it still have one hidden parameter, that is this pointer.