How to convert a values i get from a file (char) and store the values in to an array of double?

Question

I am reading data from a file, retrieving how many columns and rows I have ( data file ), everything of so far. Now I am trying to read the values one by one and store the values in to a 2D array (double). I get the values as char using getc but when I try to use atoi or atof to convert the values from char to double i get strange values.

double ther[j][number];
char c;
int tim=0,nther=0;


FILE *fp3 = fopen("data.txt", "r");
c = getc(fp3) ;

while (c!= EOF)
{ 

    ther[tim][nther]=atoi(&c);
    printf("%lf", ther[tim][nther]);


    nther++;
    c = getc(fp3);

    if(nther==number)
    {
        tim++;
        nther=0;
    }
    tim=0;
}

fclose(fp3);

any suggestion?… (i keep searching). Sorry well i have a file data.txt and this file has rows an columns of numbers:

1 2 3 4 5

6 7 8 9 10

So i need to store the data into a 2D array: Thanks to the answers i have some ideas like: use an string, then divide all values and stored every one of them. 1st line is string-> array[0][0], array[0][1], etc. Then move to the other row and do the same.

Until now i get some numeric values but none of them are stored at the data.txt.

Answer 1

#include <stdio.h>

int main(){
    int j = 2;
    int number = 5;

    double ther[j][number];
    double d;
    int tim=0,nther=0;
    FILE *fp3 = fopen("data.txt", "r");

    while (fscanf(fp3, "%lf", &d)==1){
        ther[tim][nther]=d;
        printf("%g ", ther[tim][nther++]);

        if(nther==number){
            ++tim;
            nther=0;
            printf("\n");
        }
    }
{
    int r, c;
    for(r=0;r<tim;++r){
        for(c=0;c<number;++c){
            printf("%f ", ther[r][c]);
        }
        printf("\n");
    }
}
    return 0;
}