I am trying to use a gamepad to control an application. It's not a game, just a plain application using Windows Forms. So it doesn't have a game loop/update process or anything like that. I wouldn't like to use XNA because I think it's a huge overload just to capture a button press.
I am experimenting with both SlimDX and SharpDX. As I understand, they are just wrappers for DirectX, right?
Looking at the documentation, it seems like there is no event for a button press. So I have been looking for an alternative. I have tried adding a timer (from the System.Windows.Forms.Timer class), and reading the state of the gamepad like this:
private void timer_tick(object sender, EventArgs e)
{
State s = controller.GetState();
stateLabel.Text = s.Gamepad.Buttons == GamepadButtonFlags.A ? "A" : "";
}
With a small enough interval between timer ticks (I'm using 10ms), I can see whether the button is pressed or not. However, I don't want to handle the button press multiple times should the button be held down - I need to make sure it has been released before handling the button press again. Between two ticks of the timer, I don't know if a button was pressed twice or if it was just being held down.
I thought about using the packet number in the controller state, but it will change at the slightest touch on an analog stick or shoulder trigger.
Help?
From what I can gather after reading you question over a few times is that you are wanting to log a button press only 1 time until it is released. You probably should use the packet number technique to keep track of any changes to the other input.
To get a single input from the button being held down as opposed to getting continuous input (1 as opposed to 11111111...etc) create an old state an a current state. Then compare the old state with the new state.
Something like this:
class Input
{
State old;
void GetInput()
{
State new = controller.GetState();
if (this.old.GamePad.Buttons == GamepadButtonFlags.A && new.GamePad.Buttons == GamepadButtonFlags.A)
{
// Do stuff that will be called only once.
}
this.old = new;
}
}