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scalashapelesshlist

Find type class instances for Shapeless HList


Say that I have a trait Show[T] such as the one in Scalaz: https://github.com/scalaz/scalaz/blob/scalaz-seven/core/src/main/scala/scalaz/Show.scala#L9

I also have a Shapeless HList that may look like "1" :: 2 :: 3L :: HNil.

Is there a way to find the Show instance for each element and apply shows such that I end up with "1" :: "2" :: "3L" :: HNil?

If any element were of a type that did not have an implicit Show instance in scope I would want a compile error.

I think that if I build up an HList of the Show instances I should be able to use zipApply to get the HList I want, but I don't know if there is a way to get have Scala infer the HList of Show instances instead of me building it up by hand.


Solution

  • If your goal is to apply the Show instances and you don't otherwise care about building up an HList of them, the easiest approach is probably to use a polymorphic function:

    import scalaz._, Scalaz._, shapeless._
    
    val xs = "1" :: 2 :: 3L :: HNil
    
    object show extends Poly1 {
      implicit def forShowable[A: Show] = at[A](_.shows)
    }
    
    val strings: String :: String :: String :: HNil = xs map show
    

    You could get an HList of the instances by changing the Poly1 a bit:

    object showInstance extends Poly1 {
      implicit def forShowable[A: Show] = at[A](_ => Show[A])
    }
    

    In some cases it can be useful to define your own type class to collect evidence that you've got certain type class instances:

    trait AllShowable[L <: HList, S <: HList] {
      def instances: S
    }
    
    implicit object hnilAllShowable extends AllShowable[HNil, HNil] {
      def instances = HNil
    }
    
    implicit def hlistAllShowable[H: Show, TL <: HList, TS <: HList](
      implicit ts: AllShowable[TL, TS]
    ) = new AllShowable[H :: TL, Show[H] :: TS] {
      def instances = Show[H] :: ts.instances
    }
    

    But usually mapping with a polymorphic function that requires the instances will work just fine.