My XML:
<result>
<document version="2.1.0">
<response type="currency">
<currency>
<code>AMD</code>
<price>85.1366</price>
</currency>
</response>
<response type="currency">
<currency>
<code>AUD</code>
<price>31.1207</price>
</currency>
</response>
</document>
</result>
My Class:
public class CurrencyData
{
public string Code { get; set; }
public string Price { get; set; }
}
My deserializer calling:
RestClient.ExecuteAsync<List<CurrencyData>>...
If i renamed class CurrencyData
to Currency
then all will been done right. But I want to keep this class name.
Ok, I think I got it,
You can try RestClient.ExecuteAsync<Result>()
[XmlRoot("result")]
public class Result
{
[XmlElement("document")]
public Document Document { get; set; }
}
public class Document
{
[XmlElement("response")]
public Response[] Responses { get; set; }
[XmlAttribute("version")]
public string Version { get; set; }
}
public class Response
{
[XmlElement("currency")]
public CurrencyData Currency { get; set; }
[XmlAttribute("type")]
public string Type { get; set; }
}
public class CurrencyData
{
[XmlElement("code")]
public string Code { get; set; }
[XmlElement("price")]
public decimal Price { get; set; }
}
I had to add a few XmlElement
attribute to override the casing without having to name classes and properties in lowercase. but you can drop them if you can change the xml to match the casing