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javaapikeyboardkeyboard-layout

Keyboard Layout library to find Neighboring Keys given an input key (java preferable)


Does anyone know of a library (preferably java) that can give me neighboring keys given a key input for US_ENGLISH standard keyboard?

E.g. if I input the character 'd', I should get the following characters returned: [w,e,r,s,f,x,c,v].

Alternatively a grid manipulation api would work too (so that I can instantiate a grid with a qwerty keyboard layout and use it to find my neighbors).

Note 1: I am using the words 'character' and 'key' synonymously to refer to characters.

Note 2: I know I can hard-code a method to map the 50-or-so primary keys to their neighbors. I am looking for a better solution.

Thank You.


Solution

  • I agree with BlueNovember but in case you want a more "mathematical" solution check this. First you create a grid of characters and then you return all of them that has a distance smaller than 2 from the key passed... Kinda useless but it's a nice exercise :)

    public class Test {
    
        static String chars = "qwertyuiopasdfghjkl;zxcvbnm,.";
    
        public static void main(String[] args) {
            System.out.println(getNeighboringKeys('f'));
            System.out.println(getNeighboringKeys('u'));
            System.out.println(getNeighboringKeys('m'));
            System.out.println(getNeighboringKeys('q'));
        }
    
        public static String getNeighboringKeys(char key) {
            StringBuffer result = new StringBuffer();
            for (char c : chars.toCharArray()) {
                if (c!=key && distance(c,key)<2) {
                    result.append(c);
                }
            }
            return result.toString();
        }
    
        public static double distance(char c1, char c2) {
            return Math.sqrt(Math.pow(colOf(c2)-colOf(c1),2)+Math.pow(rowOf(c2)-rowOf(c1),2));
        }
    
        public static int rowOf(char c) {
            return chars.indexOf(c) / 10;
        }
    
        public static int colOf(char c) {
            return chars.indexOf(c) % 10;
        }
    }