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python-3.xwhile-loopuser-input

How to accept input without the need to press enter Python 3


i'm wondering how to accept input without the need to press enter. i searched online, and i get something regarding raw_input, but i think that became obsolete after the arrival of python 3.0. sometimes, i run a while loop on a whole program since i want to ask the user: continue? (y/n):

for instance consider the code:

import random

d = input('Toss coin? (y/n): ')

while d != 'n' and d!= 'N':
    c = random.randint(1,2)
    if c == 1:
        print('HEADS!')
    else:
        print('TAILS!')

    d = input('Toss coin? (y/n): ')

but i just want to add more flare to my program by just not having the user press enter everytime. just press y or n and the program loops or breaks accordingly.

ok so this is the new code:

import random
import msvcrt

d = input('Toss coin? (y/n): ')

while d != 'n' and d!= 'N':
    c = random.randint(1,2)
    if c == 1:
        print('HEADS!')
    else:
        print('TAILS!')

    print('Toss coin? (y/n): ')
    d = msvcrt.getwch()

but msvcrt still doesn't work


Solution

  • If you are using windows, msvcrt is the answer:

    import msvcrt
    
    print ("Please enter a value.")
    char = msvcrt.getch()
    print char
    

    If you are not using windows, take a look at the following snippet at this source:

    getch = _Getch()
    print ("Please enter something: ")
    x = getch()
    print x