I have a doubt regarding unless and if blocks in ruby language. Please excuse me if I'm that stupid to ask this question.
Lets assume we have two boolean variables a = true
and b = true
.
condition: I want to check whether both of them are true. Using if statement we can check that as given below.
if a == true && b == true
print "Hai"
end
doubt: instead of the above statement, can I use the one given below?
unless a == false && b == false
print "Hai"
end
Will both the blocks given above give the same result?
Instead of
if a == true && b == true
print "Hai"
end
you can write
if a && b
print "Hai"
end
This is the same as
unless !(a && b)
print "Hai"
end
Which is (using De Morgan's laws) the same as
unless !a || !b
print "Hai"
end