Change image src from multiple image list using jquery

Question

I want to change image src on main image mouse hover i have one script but it work only when two images but i need to change image src from multiple images.

My existing code is like

<img width="220" height="220" alt="DE709 Folding Sunglasses" src="/images/7804/1__63824.1339534463.220.220.jpg" onmouseover="this.src='/images/x/319/1__53737.JPG'" onmouseout="this.src='/images/7804/1__63824.1339534463.220.220.jpg'">

And above code is working fine for me but i want something like this

    <ul class="ProductList List">
        <li class="Odd" style="height: 220px;">
             <div data-product="1233" class="ProductImage QuickView" style="height: 244px; width: 220px;"> 
          <a href="#">
             <img alt="DE709 Folding Sunglasses" src="/images/7804/1__63824.1339534463.220.220.jpg">
             <img style="display: none;" width="220" height="220" src="/product_images/x/319/1__53737.JPG">
              <img style="display: none;" width="220" height="220" src="/product_images/w/307/1__63824.jpg">
              <img style="display: none;" width="220" height="220" src="/product_images/l/017/DE-DISPLAY-BOX__82034.jpg">
          </a>
         <div>
       </li>
       <li>
            <div data-product="1234" class="ProductImage QuickView" style="height: 244px; width: 220px;">
            <a href="#">
            <img alt="Designer Eyewear™ Folding Sunglasses DE706" src="/images/10064/DE706__95146.1346109648.220.220.jpg" />
            <img width="220" height="220" src="/product_images/u/773/2__48597.JPG" style="display: none;">
             <img width="220" height="220" src="product_images/w/403/1__41999.JPG" style="display: none;">
             <img width="220" height="220" src="product_images/r/222/DE-DISPLAY-BOX__17353.jpg" style="display: none;"></a>
          </div>
      </li>


    </ul>

when i hover on image.jpg first time it will show me image1.jpg when mouse out it shows image.jpg and when second time it display me image2.jpg and so on when i hover 6 time it shows me image1.jpg again.

before edit i have only one div and all the solution are work for me but i need some changes on it. If I have more than one than what i do for it.

I search on Google from long time but not getting proper idea so please suggest me how can i achieve my goal.

any good link or suggetion help me great.

Answer 1

Now see updated code for multiple div

<div>
       <img class="parent " src="image.jpg"" data-pos = '0' />
       <div>
         <img class="img" style="display:none" src="image1.jpg"" />
         <img class="img" style="display:none" src="image2.jpg"" />
         <img class="img" style="display:none" src="image3.jpg"" />
         <img class="img" style="display:none" src="image4.jpg"" />
         <img class="img" style="display:none" src="image5.jpg"" />
      </div>
<div>

<hr>

<div>
       <img class="parent " src="image.jpg"" data-pos = '0' />
       <div>
         <img class="img" style="display:none" src="image1.jpg"" />
         <img class="img" style="display:none" src="image2.jpg"" />
         <img class="img" style="display:none" src="image3.jpg"" />
         <img class="img" style="display:none" src="image4.jpg"" />
         <img class="img" style="display:none" src="image5.jpg"" />
      </div>

<div>

and Jquery for it is

$(document).ready(function(){
    var pos = 0;
    $('.parent').bind('mouseover',function(){
        pos = $(this).data('pos');
        $(this).next('div').find('.img').eq(pos%5).show();
        $(this).hide();
        pos++;
        $(this).data('pos',pos);
    });
    $('.img').bind('mouseout',function(){
        $(this).hide();
        $('.parent').show();

    });
});

----------------------------- Below Was Old Answer --------------------

Use following HTML code

<div>
<img class="parent " src="image.jpg" />
  <img class="img" style="display:none" src="image1.jpg" />
  <img class="img" style="display:none" src="image2.jpg" />
  <img class="img" style="display:none" src="image3.jpg" />
  <img class="img" style="display:none" src="image4.jpg" />
  <img class="img" style="display:none" src="image5.jpg" />

</div>
<div>

And this jQuery stuff

$(document).ready(function(){
    var pos = 0;

    //hide parent image and show one of the child image
    $('.parent').bind('mouseover',function(){
        $('.img').eq(pos%5).show();
        $(this).hide();
        pos++;
    });

    //hide child images and show parent image
    $('.img').bind('mouseout',function(){
        $('.img').hide();
        $('.parent').show();
    });
});

here is fiddle