This is part of my homework. All I need is a bit of advice. I need to write some nested loop constructs, to print the following:
"122333444455555"
"+**+++****+++++"
"--***++++-----******+++++++"
Here is my code to print the first set of symbols
public static void main (String[] args)
{
int i,j;
for(i=1;i<6;++i)
{
for(j=1;j<i+1;++j)
{
System.out.print(i);
}
}
}
This works perfectly fine. I'm just having trouble figuring out the second and third set of symbols.
Apologies for my lack of experience, I'm fairly new to Java.
public static void main(String[] args) throws IOException {
int i, j;
for (i = 1; i < 6; ++i) {
for (j = 1; j < i + 1; ++j) {
System.out.print(i);
}
}
System.out.println();
for (i = 1; i < 6; i++) {
if (i % 2 == 1) {
for (j = 1; j < i + 1; ++j){
System.out.print("+");
}
} else {
for (j = 1; j < i + 1; ++j){
System.out.print("*");
}
}
}
System.out.println();
for (i = 2; i < 8; i++) {
if (i % 3 == 1) {
for (j = 1; j <= i; ++j){
System.out.print("+");
}
} else if (i % 3 == 2) {
for (j = 1; j <= i; ++j){
System.out.print("-");
}
} else {
for (j = 1; j <= i; ++j){
System.out.print("*");
}
}
}
}
Cycle #1: You have to print out numbers from one to five and each number N has to be printed out N times.
for (i = 1; i < 6; ++i) { // this would set `i` to numbers from 1-5
for (j = 1; j < i + 1; ++j) { // for each cycle (next number) it prints
//it out N times where N is the cycle number. 1 is the first cycle,
//2 is the second and so on.
Cycle #2: Same problem but instead of printing out number of the cycle you have to print out + or * based on if the cycle number is odd or even.
To check if the number is even you can use:
int number = 1;
if(number % 2 == 0){ // is true if the number is even
This checks whats the remainder from the division of number
by two.
Cycle #3: Same as #2 but you start from the second cycle, not from the first and you check for the remainder after division by 3.