I am trying to sort
SELECT * FROM myTable ORDER BY DATE(date) //
date
is stored with string
Here is the LogCat
11-22 12:50:50.906: I/DB(31388): get :17 Nov 2013 09:36:01
11-22 12:50:50.906: I/DB(31388): get :13 Nov 2013 07:41:29
11-22 12:50:50.907: I/DB(31388): get :12 Nov 2013 11:09:46
11-22 12:50:50.907: I/DB(31388): get :08 Nov 2013 09:13:26
11-22 12:50:50.908: I/DB(31388): get :02 Nov 2013 08:54:26
11-22 12:50:50.908: I/DB(31388): get :27 Oct 2013 08:02:09
11-22 12:50:50.908: I/DB(31388): get :26 Oct 2013 07:42:18
11-22 12:50:50.908: I/DB(31388): get :21 Oct 2013 06:45:18
11-22 12:50:50.909: I/DB(31388): get :19 Oct 2013 07:38:43
11-22 12:50:50.909: I/DB(31388): get :16 Oct 2013 03:12:16
UPDATE from HERE============>>>
This is not return long
value. It is always return 0
.
try {
DateFormat sdf = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss z", Locale.US);
Date date = sdf.parse(dateTime);
long milliseconds = date.getTime();
return milliseconds;
} catch (Exception e) {
e.printStackTrace();
Log.i("DB", "err :" + e);
return 0;
}
I want to sort with latest date can anyone spent some time for me.. Thanks in advance.
You can convert you string date into Long Then Put up it into Database: if you have Date String something like this 22/11/2013 12:10:00 you can simply convert it with the help of SimpleDateFormater
public static long convertStringDateToLong(String dateTime){
try {
DateFormat f = new SimpleDateFormat("dd/MM/yyyy HH:mm:ss");
Date d = f.parse(dateTime);
long milliseconds = d.getTime();
return milliseconds;
} catch (Exception e) {
return 0;
}
}
SimpleDateFormate Depends on you Date String formate.