for loop with comparing to set of arrays

Question

Q. what is the right condition for DISPLAYING ONLY equal elements in my array.

heres the code.

    int num[]=new int[5];
    int numm[]=new int[5];

    for(int x=0;x<num.length;x++){
        num[x]=Integer.parseInt(JOptionPane.showInputDialog("Enter Values for num["+(x+1)+"]"));
    }

    for(int x1=0;x1<num.length;x1++){
        num[x1]=Integer.parseInt(JOptionPane.showInputDialog("Enter Values for num1["+(x1+1)+"]"));
    }

    String tosho="";
        for(int a=0;a<num.length;a++){
            for(int a1=0;a1<numm.length;a1++){
            if(num[0]==numm[0]){
              num[0]=numm[0];}


            else if(num[1]==numm[1]){
                num[1]=numm[1];}

            else if(num[2]==numm[2]){
                num[2]=numm[2];}

            else if(num[3]==numm[3]){
                num[3]=numm[3];}

            else if(num[4]==numm[4]){
                num[4]=numm[4];}       
        }

    }tosho+=(num[0])+""+(num[1])+""+(num[2])+""+(num[3])+""+(num[4]);

    JOptionPane.showMessageDialog(null, "both "+tosho+" found in array.");

when I input 1,2,3,4,5 in first aary

then 1,22,3,4,5 in second array

still it display the 2 or 22, even though they are not equal,,,

Answer 1

num[x1]=Integer.parseInt(JOptionPane.showInputDialog("Enter Values for num1["+(x1+1)+"]"));

maybe numm[x1]?

You can use this code to fill tosho:

String tosho="";
for(int a=0;a<num.length;a++) {
    if(num[a]==numm[a]) {
        tosho+=num[a]+",";
    }
}