I have two vectors like the following:
vdA = { 8.0, 7.0, 6.0 }
vdB = { 0.0, 1.0, 2.0, 3.0 }
I basicly want a vector vdX that result is to sum all element of vdA by all values of vdB.
vdX = {
8.0, 9.0, 10.0 11.0,
7.0, 8.0, 9.0, 10.0,
6.0, 7.0, 8.0, 9.0
}
With MathNet.Numerics I couldn't find an function to do this.
In C# I make this code to do this
Vector<double> vdA = new DenseVector(new[] { 8.0, 7.0, 6.0 });
Vector<double> vdB = new DenseVector(new[] { 0.0, 1.0, 2.0, 3.0 });
List<double> resultSumVector = new List<double>();
foreach (double vectorValueA in vdA.Enumerate())
foreach (double vectorValueB in vdB.Enumerate())
resultSumVector.Add(vectorValueA + vectorValueB);
Vector<double> vdX = new DenseVector(resultSumVector.ToArray());
Are there any other options to accomplish this faster with Math.Net Numerics in c#?
You basically need a cross join in Linq. You can write an extension method, this way it looks like it is a Math.Net method:
namespace MathNet.Numerics
{
public static class DenseVectorExtensions
{
public static DenseVector AddAlls(this DenseVector vdA, DenseVector vdB)
{
return DenseVector.OfEnumerable(
vdA.SelectMany(x => vdB, (y, z) => { return y + z; })
);
}
}
}
Usage :
var vdA = new DenseVector(new[] { 8.0, 7.0, 6.0 });
var vdB = new DenseVector(new[] { 0.0, 1.0, 2.0, 3.0 });
var vdX = vdA.AddAlls(vdB);
This is not particularly faster.