How to initialize a structure on definition?

Is there a way to declare a structure with default initalisation values?

I have a header file which defines a structur like this:

typedef struct struc_s
{
    size_t cost const = 2000;
    size_t dmg const = 100;
    size_t def const = 100;
    size_t hull const = 1500;
    size_t shield const = 300;
    size_t capacity const = 2;
    size_t destruc const = 10;
} struc_t;

But this ofcourse doesn't work.

I would also be fine with a way of declaring a var of type struc_t in this header file. But as I remember right. I would have to decalre it in the c file as extern

What I want to do is every where where this header is included i want to be able to do var = struc_s.dmg and and the result should be that var holds the value 100. But I dont want to declare struc_s anywhere else then in the header. Is there a way to archive this behavior?

Solution

Not in the way you want.

When you do a typedef, you're defining the shape of a memory region, a process distinct from allocating and filling it.

A possible alternative:

typedef struct 
{
    size_t cost;
    size_t dmg;
    size_t def;
    size_t hull;
    size_t shield;
    size_t capacity;
    size_t destruc;
} struc_t;


#ifndef DEFAULT_STRUC_VALUES_DEFINED
#define DEFAULT_STRUC_VALUES_DEFINED 

const struc_t DEFAULT_STRUC = {
    .cost = 2000,
    .dmg = 100,
    .def = 100,
    .hull = 1500,
    .shield = 300,
    .capacity = 2,
    .destruc = 10
};
#endif

and then when you want to create a new one:

struc_t *new_struc = malloc(sizeof(struc_t));
memcpy(new_struc, DEFAULT_STRUC, sizeof(struc_t));

As a sidenote, is there a reason you're using size_t for your structure members? There's nothing inherently wrong with it, but it may change from platform to platform.