Lets say I wanted to open a function (it opens a file, does something with it, then spits out the results to a different file). Using argv and argc, and from going through all the tutorials online, I'm assuming that if i print argv[0] i get the file name. My question is how do i set lets say the next argv[1.2.n] to a function. So if the user were to type in open (after the user is in the program directory), it would open that function. Something like:
void file();
...
if (argv[1] == open){
file();
}
argv is of type char*[] (array of char* pointers). You cannot directly compare string constants (type char*), which you need to quote. Instead, I suggest you to convert it to a c++ string type:
#include <string>
void file(){
// ...
}
int main(int argc, char *argv[]) {
if(argc>=2)
{
if(std::string(argv[1]) == "open")
{
file();
}
}
else
{
// print usage
}
}