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cprintfformat-string

How to escape the % (percent) sign in C's printf

How do you escape the % sign when using printf in C?

printf("hello\%"); /* not like this */
Solution

  • You can escape it by posting a double '%' like this: %%

    Using your example:

    printf("hello%%");

    Escaping the '%' sign is only for printf. If you do:

    char a[5];
strcpy(a, "%%");
printf("This is a's value: %s\n", a);

    It will print: This is a's value: %%