I am using Datastax cassandra distribution on Mac OS X (dsc-cassandra-1.2.6). I want to use timeuuid types, and was experimenting with queries against them.
Here is my table:
CREATE TABLE test_t (
canon_key text,
t timeuuid,
PRIMARY KEY (canon_key, t)
)
Now lets say I get a row.
cqlsh:pagedb> select canon_key, t, dateOf(t), unixTimestampOf(t) from test_t where canon_key = 'xxx' and t >= minTimeuuid('2013-08-08 18:43:58-0700');
canon_key | t | dateOf(t) | unixTimestampOf(t)
-----------+--------------------------------------+--------------------------+--------------------
xxx | 287d3c30-0095-11e3-9268-a7d2e09193eb | 2013-08-08 18:43:58-0700 | 1376012638067
Now, I want to delete this row. I don't see a good way of doing it, because there is no equality operator for the timeuuid type.
The nature of the data I am adding is such that I (possibly) wouldn't even mind doing this:
cqlsh:pagedb> select canon_key, t, dateOf(t), unixTimestampOf(t) from test_t where canon_key = 'xxx' and t >= minTimeuuid('2013-08-08 18:43:58-0700') and t <= maxTimeuuid('2013-08-08 18:43:58-0700');
But according to the documentation (http://cassandra.apache.org/doc/cql3/CQL.html#usingdates), that will not work. Quoting: " Please note that t >= maxTimeuuid('2013-01-01 00:05+0000') would still not select a timeuuid generated exactly at ‘2013-01-01 00:05+0000’ and is essentially equivalent to t > maxTimeuuid('2013-01-01 00:05+0000').".
So.. how do I delete this row?
Your premise is mistaken -- minTimeuuid
and maxTimeuuid
do exist to allow inequality operations on timeuuids, but that does not mean that simple equality is not supported:
cqlsh:foo> insert into test_t (canon_key, t) values ('k', now());
cqlsh:foo> select * from test_t;
canon_key | t
-----------+--------------------------------------
k | 27609890-0209-11e3-b862-59d5a2b25b8f
(1 rows)
cqlsh:foo> delete from test_t where canon_key = 'k' and t = 27609890-0209-11e3-b862-59d5a2b25b8f;
cqlsh:foo> select * from test_t;
(0 rows)