Is php static variable resetting ignored when a function is recalled?

Question

I got this code at http://w3schools.com/php/php_variables.asp

The code is

<?php
function myTest()
{
static $x=0;
echo $x;
$x++;
}
myTest();
myTest();
myTest();
?>

and the website claims that the output will be 012

No my question is whenever function myTest() runs then $x should be set to 0 and hence the output should be 000. Can someone tell me that why will running the function myTest() again and again increase the value, even though $x is again and again reset to the value of 0.

Please help me as I am a newbie. I tried asking a few people who know programming and they agreed with me that the output should be 000.

Answer 1

The output is right, it should be 012: http://codepad.org/NVbfDGY7

See this example in the official documentation: http://www.php.net/manual/en/language.variables.scope.php#example-103

<?php
function test()
{
    static $a = 0;
    echo $a;
    $a++;
}
?>

test();  // set $a to 0, print it (0), and increment it, now $a == 1
test();  // print $a (1), and increment it, now $a == 2
test();  // print $a (2), and increment it, now $a == 3

The doc says:

Now, $a is initialized only in first call of function and every time the test() function is called it will print the value of $a and increment it.