How to determine weather ostream is a file or a console stream. In the following program I want to print "Hello file!" while writing to a file and "Hello console!" while writing to console. What condition should I specify at line 17?
#include <fstream>
#include<iostream>
#include <string>
using namespace std;
class A{
public:
A(string msg):_str(msg){}
string str()const {return _str;};
private:
string _str;
};
ostream & operator << (ostream & os, const A & a)
{
if (os is ofstream) //this is line 17
os << "Hello file! " << a.str() << endl;
else
os << "Hello console! " << a.str() << endl;
return os;
}
int main()
{
A a("message");
ofstream ofile("test.txt");
if (!ofile)
cerr << "Unable to open file";
else
ofile << a; // "Hello file"
cout << a << endl; // "Hello console"
}
Maybe not pretty, but
std::streambuf const * coutbuf = std::cout.rdbuf();
std::streambuf const * cerrbuf = std::cerr.rdbuf();
ostream & operator << (ostream & os, const A & a)
{
std::streambuf const * osbuf = os.rdbuf();
if ( osbuf == coutbuf || osbuf == cerrbuf )
os << "Hello console! " << a.str() << endl;
else
os << "Hello file! " << a.str() << endl;
return os;
}
We could use &os == &std::cout
, but the Standard output might be redirected to file, so I think it is better to use the streambuf object instead. (See this answer for better understanding as to how the redirection works, and why comparing streambuf solves the problem safely! )