I'd like to make a ball bounce angle change each time it hits a wall.
It will change based on how near the middle of the wall it hits...
Right now, I'm hard coding the change in X and Y when it hits a surface... My goal is to get the degrees from current X and Y, apply a change to the degrees (Right now I'm add a random number to the degrees), then calculate the new incrementing values for X and Y. I know how to get the newX and newY, but not how to get the incrementing values.
The green is the starting x
y
of (5,5)
... the blue is the next frame of (4,4)
.
45
based on that. currX
(5) - wallX
(0) = distX
(5)
currY
(5) - wallY
(0) = distY
(5)
Take the cosine of my angle + random increment, we'll say 55 degrees, * distX
cos(55 degrees) = .5735
... .5735 x distX (5) = 2.86
And sin of my angle * distY
sin(55 degrees) = .8191
... .8191 x distY (5) = 4.09
newX = cos result (2.86) + originX (5) = 7.86
newY = sin result (4.09) + originY (5) = 9.09
newX, newY = (7.86, 9.09)
Okay... so I have my new coordinates...
But those don't equate to what my new incrementing value of x
and y
should be based on my angle in incidence.
Code snippet: You can see that I'm hard coding the x,y
increments (dragger.x += 2; )
function tick() {
var rand = Math.floor((Math.random()*10)+1);
console.log("ticking..." + rand);
if (dragger.x >= 400-20) {
dragger.xDir = "right";
}
if (dragger.x < 20) {
dragger.xDir = "left";
}
if (dragger.y >= 150-20) {
dragger.yDir = "up";
}
if (dragger.y < 20) {
dragger.yDir = "down";
}
var oldX = dragger.y;
var oldY = dragger.x;
if (dragger.xDir == "left") {
dragger.x += 2;
}
else {
dragger.x -= 2;
}
if (dragger.yDir == "up") {
dragger.y -= 2;
}
else {
dragger.y += 2;
}
//post update...
var newX = dragger.y;
var newY = dragger.x;
var angle = getAngle(newX, oldX, newY, oldY)
angle+=rand;
$('#getAngle').empty();
$('#getAngle').append("bounce angle (degrees): " + angle);
//console.log(xDir);
// update the stage:
stage.update();
}
function getAngle(x2, x1, y2, y1) {
var deltaX = Math.abs(x2-x1);
var deltaY = Math.abs(y2-y1);
var radians = Math.atan2(deltaX, deltaY);
var degrees = radians * (180/Math.PI);
return degrees;
}
This is a pretty interesting problem due to it's specificity.
Making a ball bounce in a programming language can be done quite easily. Like this example.
But clearly, your question is not about 'making it work'; you want explicit control over the coordinates and the angles such that you can alter them for whatever purpose you had in mind.
Because I am quite vulnerable to nerd sniping, I dusted off my geometric skills and came up with the following scrap of pseudocode (I made this from scratch to make sure I have total control):
theta = starting angle
a = current x-coordinate of ball
b = current y-coordinate of ball
quadrant = quadrant-direction to which ball is moving
/> Determine number between 1 and 360: theta
/> Calculate quadrant
.> 0-90 : quadrant 1: horizontal: 90-a vertical: b alpha: 90 - theta
.> 90-180: quadrant 4: horizontal: 90-a vertical: 30-b alpha: theta - 90
.> 180-270: quadrant 3: horizontal: a vertical: 30-b alpha: 270 - theta
.> 270-360: quadrant 2: horizontal: a vertical: b alpha: theta - 270
/> Calculate distance to side |
/> Calculate distance to top/bottom |
.> to side: n(alpha) = horizontal/cos(alpha)
.> to top/bottom: m(alpha) = vertical /sin(alpha)
/> Determine where ball is going to hit (n = side, m = top/bottom)
.> n >= m : bounces at top/bottom
.> m >= n : bounces at side
.> switch (quadrant)
.> 1 : n = right side m = top
.> 2 : n = left side m = top
.> 3 : n = left side m = bottom
.> 4 : n = right side m = bottom
/> Calculate coordinates of hit
/> Define new angle
// Normally, angle of impact = angle of reflection
// Let's define the angle of impact with respect to the origin (0,0)
.> switch (quadrant)
.> 1 :
.> n >= m (at top/bottom) : x = a + vertical*tan(alpha) y = 0 theta = 180-theta
.> m >= n (at side) : x = 90 y = b - horizontal*tan(alpha) theta = 270+alpha
.> 2 :
.> n >= m (at top/bottom) : x = a - vertical/tan(alpha) y = 0 theta = 270-alpha
.> m >= n (at side) : x = 0 y = b - horizontal*tan(alpha) theta = 90-alpha
.> 3 :
.> n >= m (at top/bottom) : x = a - vertical/tan(alpha) y = 30 theta = 270+alpha
.> m >= n (at side) : x = 0 y = b + horizontal*tan(alpha) theta = 90+alpha
.> 4 :
.> n >= m (at top/bottom) : x = a + vertical/tan(alpha) y = 30 theta = 90-alpha
.> m >= n (at side) : x = 90 y = b + horizontal*tan(alpha) theta = 270-alpha
/> Define new coordinates (for reusage of function)
.> a = x
.> b = y
.> (optional) if you would like the angles to differ, enter extra term here:
.> extra = ...
.> theta = theta + extra
Implementing this code will allow you to work with the easiness of degrees and still be able to determine the coordinates.
It works as follows:
First determine the initial position of the ball (a,b) and it's initial direction (theta)
Now the program will calculate:
And then it starts over again to calculate the new hit.
In JavaScript, the code would look like this:
var width = 500;
var height = 200;
var extra = 0;
var a;
var b;
var x;
var y;
var angle;
var n;
var m;
var quadrant;
var horizontal;
var vertical;
var alpha;
var side;
var topbottom;
var sides;
var i = 1;
var txt=document.getElementById("info");
txt.innerHTML="x: "+a+"<br>y: "+b+"<br>angle: "+angle+"<br>quadrant: "+quadrant;
function buttonClick()
{
if (i == 1)
{
a = 75;
b = 75;
//determine first angle randonmly
angle = Math.floor((Math.random()*360)+1);;
} else
{
a = xcoord();
b = ycoord();
}
var oldAngle = angle;
angle = findNewCoordinate(a, b, angle);
sides = hitWhere();
var txt=document.getElementById("info");
txt.innerHTML="x: "+a+"<br>y: "+b+"<br>horizontal: "+horizontal+"<br>vertical: "+vertical+"<br>n: "+n+"<br>m: "+m+"<br>angle: "+oldAngle+"<br>alpha: "+alpha+"<br>quadrant: "+quadrant+"<br>side: "+topbottom+side+"<br>"+sides+"<br>"+i;
i++;
}
function findNewCoordinate(a, b, angle)
{
if (angle >= 0 && angle < 90) { quadrant = 1; horizontal = width-a; vertical = b; alpha = (90 - angle); }
else if (angle >= 90 && angle < 180) { quadrant = 4; horizontal = width-a; vertical = height-b; alpha = (angle-90); }
else if (angle >= 180 && angle < 270) { quadrant = 3; horizontal = a; vertical = height-b; alpha = (270-angle); }
else if (angle >= 270 && angle <= 360) { quadrant = 2; horizontal = a; vertical = b; alpha = (angle-270); }
var cosa = Math.cos(alpha * Math.PI / 180);
var sina = Math.sin(alpha * Math.PI / 180);
var tana = Math.tan(alpha * Math.PI / 180);
var tant = Math.tan(angle * Math.PI / 180);
n = horizontal/cosa;
m = vertical/sina;
switch (quadrant)
{
case 1:
if (m >= n) //hit at side
{
y = b - horizontal*tana;
x = width;
angle = 270+alpha;
} else
{
y = 0;
x = a + vertical*tant;
angle = 180-angle;
}
side = "right side"; topbottom = "top";
break;
case 2:
if (m >= n) //hit at side
{
y = b-horizontal*tana;
x = 0;
angle = 90-alpha;
} else
{
y = 0;
x = a - vertical/tana;
angle = 270-alpha;
}
side = "left side"; topbottom = "top";
break;
case 3: side = "left side"; topbottom = "bottom";
if (m >= n) //hit at side
{
x = 0;
y = b + tana*horizontal;
angle = 90+alpha;
} else
{
y = height;
x = a - vertical/tana;
angle = 270+alpha;
} break;
case 4: side = "right side"; topbottom = "bottom";
if (m >= n) //hit at side
{
y = b+horizontal*tana;
x = width;
angle = 270-alpha;
} else
{
y = height;
x = a + vertical/tana;
angle = 90-alpha;
} break;
}
//add extra degrees to the angle (optional)
angle += extra;
context.beginPath();
context.arc(a, b, 5, 0, Math.PI*2, true);
context.stroke();
context.closePath();
context.fill();
drawLine(a,b,x,y);
return angle;
}
Note that there are many more ways to make a bouncing program. But, because I tackled the question geometrically and without 'shortcuts', the unique characteristics of my program make it very easy for you to alter it to your likings:
var extra
).Also note that I did not make the program very concise because this simply wasn't my goal. I wanted to create a bouncing ball program that, although lenghty, is an exact realisation of the geometric intuition behind it.
You can find a demo of my program in this JSFiddle. Note that the beginning angle is determined randomly. Hence restarting the program will give a different angle.
Well, that's about it.
Good luck with building the rest of your program!