I have two lists:
(setq x (list "a" "b" "c"))
(setq y (list "1" "2" "3" "4"))
How can I create a list of cons cells (("a" . "1") ("b" . "2") ("c" . "3") ("a" . "4"))
with the shorter list recycled?
Here's my take:
(require 'cl-lib)
(cl-mapcar #'list (setcdr (last x) x) y)
I'd add a check for which of them is larger, but that would spoil the brevity:).