I'm trying to take a list of elements in an array like this:
['GRADE', 'GRATE', 'GRAPE', /*About 1000 other entries here ...*/ ]
and match them to their occurrences in a column in an Oracle database full of entries like this:
1|'ANTERIOR'
2|'ANTEROGRADE'
3|'INGRATE'
4|'RETROGRADE'
5|'REIGN'
...|...
/*About 1,000,000 other entries here*/
For each entry in that array of G words, I'd like to loop through the word column of the Oracle database and try to find the right-sided matches for each entry in the array. In this example, entries 2, 3, and 4 in the database would all match.
In any other programming language, it would look something like this:
for entry in array:
for each in column:
if entry.right_match(each):
print entry
How do I do this in PL/SQL?
In PL/SQL it can be done in this way:
declare
SUBTYPE my_varchar2_t IS varchar2( 100 );
TYPE Roster IS TABLE OF my_varchar2_t;
names Roster := Roster( 'GRADE', 'GRATE', 'GRAPE');
begin
FOR c IN ( SELECT id, name FROM my_table )
LOOP
FOR i IN names.FIRST .. names.LAST LOOP
IF regexp_like( c.name, names( i ) ) THEN
DBMS_OUTPUT.PUT_LINE( c.id || ' ' || c.name );
END IF;
END LOOP;
END LOOP;
end;
/
but this is row by row processing, for large table it would be very slow.
I think it might be better to do it in a way shown below:
create table test123 as
select 1 id ,'ANTERIOR' name from dual union all
select 2,'ANTEROGRADE' from dual union all
select 3,'INGRATE' from dual union all
select 4,'RETROGRADE' from dual union all
select 5,'REIGN' from dual ;
create type my_table_typ is table of varchar2( 100 );
/
select *
from table( my_table_typ( 'GRADE', 'GRATE', 'GRAPE' )) x
join test123 y on regexp_like( y.name, x.column_value )
;
COLUMN_VALUE ID NAME
------------- ---------- -----------
GRADE 2 ANTEROGRADE
GRATE 3 INGRATE
GRADE 4 RETROGRADE