I have learned that I can never access a private variable, only with a get-function in the class. But then why can I access it in the copy constructor?
Example:
Field::Field(const Field& f)
{
pFirst = new T[f.capacity()];
pLast = pFirst + (f.pLast - f.pFirst);
pEnd = pFirst + (f.pEnd - f.pFirst);
std::copy(f.pFirst, f.pLast, pFirst);
}
My declaration:
private:
T *pFirst,*pLast,*pEnd;
IMHO, existing answers do a poor job explaining the "Why" of this - focusing too much on reiterating what behaviour's valid. "access modifiers work on class level, and not on object level." - yes, but why?
The overarching concept here is that it's the programmer(s) designing, writing and maintaining a class who is(are) expected to understand the OO encapsulation desired and empowered to coordinate its implementation. So, if you're writing class X
, you're encoding not just how an individual X x
object can be used by code with access to it, but also how:
X
objects cooperate to provide intended behaviours while honouring the post-conditions and invariants from your design.It's not just the copy constructor either - a great many operations can involve two or more instances of your class: if you're comparing, adding/multiplying/dividing, copy-constructing, cloning, assigning etc. then it's often the case that you either simply must have access to private and/or protected data in the other object, or want it to allow a simpler, faster or generally better function implementation.
Specifically, these operations may want to take advantage of priviledged access to do things like:
shared_ptr
s to reference data etc.auto_ptr<>
"moves" ownership to the object under constructionunordered_map
member but publicly only expose begin()
and end()
iterators - with direct access to size()
you could reserve
capacity for faster copying; worse still if they only expose at()
and insert()
and otherwise throw
....