I am having problem to understand the following program in Chapter 9(threads) of SCJP book K&B
QUESTION:
class Dudes{
static long flag = 0;
// insert code here
void chat(long id){
if(flag == 0)
flag = id;
for( int x = 1; x < 3; x++){
if( flag == id)
System.out.print("yo ");
else
System.out.print("dude ");
}
}
}
public class DudesChat implements Runnable{
static Dudes d;
public static void main( String[] args){
new DudesChat().go();
}
void go(){
d = new Dudes();
new Thread( new DudesChat()).start();
new Thread( new DudesChat()).start();
}
public void run(){
d.chat(Thread.currentThread().getId());
}
}
And given these two fragments:
I. synchronized void chat (long id){
II. void chat(long id){
OPTIONS:
When fragment I or fragment II is inserted at line 5, which are true? (Choose all that apply.)
A. An exception is thrown at runtime
B. With fragment I, compilation fails
C. With fragment II, compilation fails
D. With fragment I, the ouput could be yo dude dude yo
E. With fragment I, the output could be dude dude yo yo
F. With fragment II, the output could be yo dude dude yo
The Official Answer is F(But I cannot understand why, It would be really grateful if someone could explain me the concept)
Consider the following scenario:
Thread 1 ID : 1
Thread 2 ID : 2
Following steps would take place:
Thread 1 gets CPU cycle and executeschat(1)
flag=1
x = 1 : since flag == 1 soyo
is printed
Thread 1 is preempted by Thread 2
Thread 2 gets CPU cycle and executeschat(2)
flag = 1 (NOT 2 becauseflag==0
condition fails)
x = 1 : since flag!=2 sodude
will be printed
x = 2 : since flag!=2 sodude
will be printed
Thread 1 gets the CPU cycle
flag = 1
x = 2 : since flag == 1 soyo
will be printed.
Hence the output is `yo dude dude yo`