I'm doing all the K&R exercises and I have finally been able to print a horizontal histogram. It look awful too, but I'll let you judge it. I have not been able to print a histogram of the lengths of words in its input vertically.
How can I modify my program to do this?
Question: Write a program to print a histogram of the lengths if words in its input. It is easy to draw the histogram with the bars horizontal; a vertical orientation is more challenging.
histogram.c
#include <stdio.h>
#define MAX 10
#define IN 1
#define OUT 0
int main()
{
int c, len, state;
int nlength[MAX];
c = len = 0;
state = 1;
for(int i = 0; i < 10; ++i)
nlength[i] = 0;
while ((c = getchar()) != EOF) {
++len;
if (c == ' ' || c == '\n' || c == '\t') {
--len;
state = OUT;
}
if(state == OUT) {
if(len != 0 && len <= MAX)
++nlength[len];
len = 0;
state = IN;
}
}
for (int i = 0; i <= MAX; ++i) {
printf("%d ", i);
for (int a = 0; a < nlength[i]; ++a)
printf("*");
printf("\n");
}
return 0;
}
OUTPUT:
./histogram < histogram.c
0
1 *************************************
2 *************************
3 **************
4 ************
5 *****
6 ******
7 ****
8 **
9 *
10 ***
First you need to know the height of the histogram which is the maximum value. Then you print each row and you decide to put a *
or a according to the value.
int h_max = 0;
for (int a = 0; a < MAX; a++) {
if (h_max <= nlength[a]) h_max = nlength[a];
}
for (int i = h_max; i >= 0; i--) {
for (int a = 0; a < MAX; ++a) {
if (nlength[a] > i) {
printf("*");
} else {
printf(" ");
}
}
printf("\n");
}
Another solution is to print horizontally into an array and print the array in the direction you want.