So I was wondering if/how one might use the AND operation on a byte array in Java?
I've seen samples of how to use the AND operation with ints like so:
int bitmask = 0x000F;
int val = 0x2222;
// prints "2"
System.out.println(val & bitmask);
But say I have a byte Array like...
byte[] byteArray = new byte[1];
and I want to AND it so that I remove the leftmost/fist bit in the array. I figure I'd use the mask 0x7F
but how would I AND that with the byte array?
I want to AND it so that I remove the leftmost/fist bit in the array
I assume with remove you mean unset, because you can't remove the first bit. It will always be there. If I am right, you can do this:
byteArray[0] &= 127;