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pythonalgorithmceil

Implementing ceil function without using if-else

I just wanted to know that is there a way of implementing ceil function without using if-else? With if-else (for a/b) it can be implemented as:

if a%b == 0:
    return(a/b)
else:
    return(a//b + 1)
Solution

  • Like this should work if they are integers (I guess you have a rational number representation):

    a/b + (a%b!=0)

    Otherwise, replace a/b with int(a/b), or, better, as suggested below a//b.