How to check current cursor shape in Qt

Question

Qt 4.8 on Fedora 17 x64

In my QWidget::mouseMoveEvent, I am trying to check to see if the cursor is currently set to either Qt::SizeVerCursor or Qt::SizeHorCursor, but the QCursor returned by calling QWidget::cursor() cannot be compared to either Qt::SizeVerCursor or Qt::SizeHorCursor because of a compile error. It looks like this is because both Qt::SizeVerCursor and Qt::SizeHorCursor are actually Qt::CursorShape instead of QCursor.

This code fails to compile:

void MyGraphicsView::mouseMoveEvent( QMouseEvent *event )
{
    if( ( cursor() == Qt::SizeHorCursor ) || ( cursor() == Qt::SizeVerCursor ) )
    {
        qDebugGreen() << "Cursor is a size cursor!";
    }

    QGraphicsView::mouseMoveEvent( event );
}

Here is the compile error:

error: no match for ‘operator==’ in ‘QWidget::cursor() const() == (Qt::CursorShape)6u’

How can I check if the current cursor is either Qt::SizeVerCursor or Qt::SizeHorCursor?

Answer 1

Imho cursor().shape() should work.