I am new to JavaScript and I am having to use ExtJS 3.4. I have created a simple tree with 3 columns. I would like to know either what cell was selected, or even, just what row and column were selected.
I am just using the example that Sencha uses at http://dev.sencha.com/deploy/ext-3.4.0/examples/treegrid/treegrid.html :
var tree = new Ext.ux.tree.TreeGrid({
title: 'Core Team Projects',
width: 500,
height: 300,
renderTo: Ext.getBody(),
enableDD: true,
columns:[{
header: 'Task',
dataIndex: 'task',
width: 230
},{
header: 'Duration',
width: 100,
dataIndex: 'duration',
align: 'center',
sortType: 'asFloat',
tpl: new Ext.XTemplate('{duration:this.formatHours}', {
formatHours: function(v) {
if(v < 1) {
return Math.round(v * 60) + ' mins';
} else if (Math.floor(v) !== v) {
var min = v - Math.floor(v);
return Math.floor(v) + 'h ' + Math.round(min * 60) + 'm';
} else {
return v + ' hour' + (v === 1 ? '' : 's');
}
}
})
},{
header: 'Assigned To',
width: 150,
dataIndex: 'user'
}],
dataUrl: 'treegrid-data.json'
});
Is it possible to do this in ExtJS 3.4? I can get the node but I do not see where it is telling me what cell or column or row was selected.
Any help would be greatly appreciated!
you need to attach listeners e.g.
listeners: {
afterRender: function(p) {
p.body.on('click', function() { // Function tapping clicks on Panel
alert(p.getTargetEl().dom.innerHTML);
});
});
}