Search code examples
excelshow-hideif-statementvba

Combining IF else with LEFT to hide columns


I'm trying to write some code to Hide columns if the first 3 characters of cells in a range equal the contents of another. I have the code for hiding columns if cells in a range are blank as this;-

Private Sub Worksheet_Change(ByVal Target As Range)

Dim r As Range, cell As Range
On Error GoTo ErrHandler
Set r = Me.Range("C8:R8")
Application.ScreenUpdating = False
Application.EnableEvents = False

For Each cell In r
    If cell.Value = "" Then
    cell.EntireColumn.Hidden = True
    Else
    cell.EntireColumn.Hidden = False

    End If

    Next

ErrHandler:
Application.ScreenUpdating = True
Application.EnableEvents = True

End Sub

And the code for identifiying the first 3 charcters of a cell;-

Dim LResult As String

LResult = Left ("Alphabet",3)

But how do I combine the two, referencing a specific cell rather than "Alphabet"?

Cant get this to work - any suggestions?

Private Sub Worksheet_Change(ByVal Target As Range)

Dim r As Range, cell As Range

On Error GoTo ErrHandler
Set r = Me.Range("B7:CG7")

Application.ScreenUpdating = False
Application.EnableEvents = False

Row = 1
col = 1

For Each cell In r
  If cell.Value = "" And Left(cell.Value, 3) = cell(Row, col).Value Then
    cell.EntireColumn.Hidden = True
  Else
    cell.EntireColumn.Hidden = False

End If


Next
ErrHandler:
Application.ScreenUpdating = True
Application.EnableEvents = True
End Sub

Cheers


Solution

  • You have almost the working code. You are comparing cell.Value to an empty string - now just apply Left to it

    LResult = Left (cell.Value,3)
    

    Edit:

    row = 20
    col = 30
    
    For Each cell In r
      If cell.Value = "" and  Left (cell.Value,3) = Cell(row, col).Value Then
        cell.EntireColumn.Hidden = True
      Else
        cell.EntireColumn.Hidden = False
    
    End If
    

    where you want data from cell at row and col (I used 20, 30 as the example)