Java Constructor weird behaviour

Question

I've run this code

public class Redimix extends Concrete{

    Redimix(){
        System.out.println("r ");
    }

    public static void main(String[] args) {
        new Redimix();
    }

}

class Concrete extends Sand{
    Concrete() { System.out.print("c "); }
    private Concrete(String s) { }
}

abstract class Sand{
    Sand(){
        System.out.print("s ");
    }
}

and it printed out s c r but what I was expecting is that only r my question what is the logical explanation for this?

if a parent base class is an abstract class that has a constructor and then we create another class then extend it to the base class (In our Case Concrete extends Sand) and we then create another class then extend it to the concrete class name (In our case redimix) will all constructors from the hierarchy will be called?(from top to bottom)

Answer 1

A constructor of the superclass is always called as the first action of a constructor.

If you do not explicitly invoke a constructor of the superclass, the default constructor (the "no args" one) is implicitly invoked.