how to create array with n number of bytes?

Question

How to create byte[] digits; with n number of bytes?

I know I can do Enumerable.Range(1, n).ToArray(); but this creates an int[]. Is there a way to create a byte[]?

My priority is a fast performance. Keeping this in mind, is there a faster way (with slightly more code) that can create this?

Answer 1

What's wrong with just creating a byte array instance?

byte[] digits = new byte[n];

And if you want to initialize with values from 1 to n, then I think:

for(int i = 1; i <= n; i++)
   digits[i-1] = (byte)i; // index is 0-based

Will also get you the desired result as fast as possible. Of course, where n < 256!