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rvectordataframe

How to convert a list consisting of vector of different lengths to a usable data frame in R?


I have a (fairly long) list of vectors. The vectors consist of Russian words that I got by using the strsplit() function on sentences.

The following is what head() returns:

[[1]]
[1] "модно"     "создавать" "резюме"    "в"         "виде"     

[[2]]
[1] "ты"        "начианешь" "работать"  "с"         "этими"    

[[3]]
[1] "модно"            "называть"         "блогер-рилейшенз" "―"                "начинается"       "задолго"         

[[4]]
[1] "видел" "по"    "сыну," "что"   "он"   

[[5]]
[1] "четырнадцать," "я"             "поселился"     "на"            "улице"        

[[6]]
[1] "широко"     "продолжали" "род."

Note the vectors are of different length.

What I want is to be able to read the first words from each sentence, the second word, the third, etc.

The desired result would be something like this:

    P1              P2           P3                 P4    P5           P6
[1] "модно"         "создавать"  "резюме"           "в"   "виде"       NA
[2] "ты"            "начианешь"  "работать"         "с"   "этими"      NA
[3] "модно"         "называть"   "блогер-рилейшенз" "―"   "начинается" "задолго"         
[4] "видел"         "по"         "сыну,"            "что" "он"         NA
[5] "четырнадцать," "я"          "поселился"        "на"  "улице"      NA
[6] "широко"        "продолжали" "род."             NA    NA           NA

I have tried to just use data.frame() but that didn't work because the rows are of different length. I also tried rbind.fill() from the plyr package, but that function can only process matrices.

I found some other questions here (that's where I got the plyr help from), but those were all about combining for instance two data frames of different size.

Thanks for your help.


Solution

  • try this:

    word.list <- list(letters[1:4], letters[1:5], letters[1:2], letters[1:6])
    n.obs <- sapply(word.list, length)
    seq.max <- seq_len(max(n.obs))
    mat <- t(sapply(word.list, "[", i = seq.max))
    

    the trick is, that,

    c(1:2)[1:4]
    

    returns the vector + two NAs